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234 7. Divisor Functions

This completes the proof. ■

Theorem 7.4 For x \ge 1 ,

\Delta(x) = \sum_{n \le x} (\log n - d(n) + 2\gamma) = O\left(x^{1/2}\right).

Proof. By Theorem 7.3 we have

\sum_{n \le x} d(n) = x \log x + (2\gamma - 1)x + O\left(x^{1/2}\right).

By Theorem 6.4 we have

\sum_{n \le x} \log n = x \log x - x + O(\log x).

Subtracting the first equation from the second, we obtain

\sum_{n \le x} (\log n - d(n) + 2\gamma) = O\left(x^{1/2}\right) - 2\gamma\{x\} + O(\log x) = O\left(x^{1/2}\right).

An ordered factorization of the positive integer n into exactly \ell factors is an \ell -tuple (d_1, \dots, d_\ell) such that n = d_1 \cdots d_\ell . The divisor function d(n) counts the number of ordered factorizations of n into exactly two factors, since each factorization n = dd' is completely determined by the first factor d . For every positive integer \ell , we define the arithmetic function d_\ell(n) as the number of factorizations of n into exactly \ell factors. Then d_1(n) = 1 and d_2(n) = d(n) for all n .